Is This As Stupidly Hard As It Looks?

[acropolis]

7AB
*EF
------
GHICD

ABCDEFGHI = 012345689 in some order or another.

i don't see any angle to work from.

G is between 1 and 6 clearly.

and probably not 1.
not much to go on seeing as there's 360,000 arrangements to check.

[MrL_JaKiri]

B, E, F cannot equal 0 or 1, there's a bit more to get you moving.

[MrL_JaKiri]

Originally Posted by Flavius

lets reduce that to finding 1 variable only:

7A(A+1) * (A+4)(A+5) = (A+6)(A+7)(A+8)(A+2)(A+3)

you figure out the rest ..

B doesn't equal A+1, you moron.

B = (a number from 0-9)

A = (another number from 0-9)

There is NO RELATIONSHIP BETWEEN THEM EXCEPT THEIR COEXISTANCE IN THE QUESTION

[Ebany]

well that would make it a very easy question if he just told us at the end that A is 0, B is 1 etc. In fact, it wouldnt really have left us with much of a question. Although I will admit I tried plugging that into a calculator quickly to see if it came out well.

plus quickly reading back it does state 'In some order or another' IE not in the order they are listed (although they could have been, just by chance)

[queball]

Originally Posted by MrL_JaKiri

B, E, F cannot equal 0 or 1, there's a bit more to get you moving.

What's your reasoning for E?

[MrL_JaKiri]

Originally Posted by queball

What's your reasoning for E?

Hold on, I'm wrong about E =! 1 (definitely). It definitely doesn't equal zero, though (I wrote the post then edited it)

[MrL_JaKiri]

Originally Posted by Flavius

He Said Abcdefgh = 0123456789, Meaning They Are Ordered, And So Is Their Relation

He said (to paraphrase) 'abcdefgh = 012345689, but not in that order'; it isn't that difficult to read the same line as you were on before

[queball]

Originally Posted by acropolis

not much to go on seeing as there's 360,000 arrangements to check.

I'd say more like 3000, naively.

[Nodrog]

I'm not convinced its possible other than through massive trial and error.

[acropolis]

Originally Posted by queball

I'd say more like 3000, naively.

9! =~ 360,000. For a G from 1 to 6 cuts that down to 240,000, and for B and F not 0,1 that cuts it down to 200,000 then 160,000.

But it still appears that

Originally Posted by Nodrog

massive trial and error

is necessary to finish It.

Hence the title of the thread.

In fact, I'm such a loser that I would be willing to try 3000 combinations, if I knew it would work.

[queball]

Originally Posted by acropolis

9! =~ 360,000. For a G from 1 to 6 cuts that down to 240,000, and for B and F not 0,1 that cuts it down to 200,000 then 160,000.

But it still appears thatis necessary to finish It.

Hence the title of the thread.

In fact, I'm such a loser that I would be willing to try 3000 combinations, if I knew it would work.

perl -e 'for$s(701..798){for(1..99){print"$s $_\n"if"0123456789"eq (join"",sort split//,$s.$_.$s*$_)}}'
Yes, it works. Don't try it if you don't want it spoiled.
Obviously you can cut down on the actual number of combinations by not choosing 711, or 712 and 13, and so on.

[Nodrog]

queball makes me hard

[Dante Hicks]

I don't remember there being any Perl questions on that Geek test which is an absolute travesty.

[acropolis]

Originally Posted by queball

perl -e 'for$s(701..798){for(1..99){print"$s $_\n"if"0123456789"eq (join"",sort split//,$s.$_.$s*$_)}}'
Yes, it works. Don't try it if you don't want it spoiled.
Obviously you can cut down on the actual number of combinations by not choosing 711, or 712 and 13, and so on.

i don't wish to do it. i wish to look smart.

answers?

ps: but yes you are right, far less than 10,000 if you choose the right combinations.

[queball]

PMed

Not that 9! would be any trouble for a computer, of course.

[Scoot951]

Originally Posted by acropolis

7AB
*EF
------
GHICD

ABCDEFGHI = 012345689 in some order or another.

i don't see any angle to work from.

G is between 1 and 6 clearly.

and probably not 1.
not much to go on seeing as there's 360,000 arrangements to check.

I can add that EF > 23, or EF = 12 and G = 0. Also, D /=1.

[queball]

I can only reduce it to 25 big multiplications with pen and paper. :-/

Originally Posted by Scoot951

I can add that EF > 23, or EF = 12 and G = 0. Also, D /=1.

Why couldn't EF be 13 to 19?

[acropolis]

Originally Posted by queball

I can only reduce it to 25 big multiplications with pen and paper. :-/



Why couldn't EF be 13 to 19?

723*14 = 10122, so once you get to EF =14 it can't result in less than 10000 (which obviously starts with a 1)

798*14 = 11172,

so 14 is clearly bad.

for 19, all results are between 13737 and 15162. no go.

13 might be okay tho. but it obviously isn't.

ps: my working title for this thread was "Hey Queball"

[JonnyBGood]

Is GHICD one number as in g is 5 h 8 so it's 58ICD or should they be multiplied together to form a number at the end?

[queball]

Originally Posted by JonnyBGood

Is GHICD one number as in g is 5 h 8 so it's 58ICD or should they be multiplied together to form a number at the end?

One number. Otherwise you couldn't get a factor of 7.

[MrL_JaKiri]

Just straight replacement, not multiplication

[Noodles]

hmmm.. am I the only one that has f'k all idea what's going on here...?

[JonnyBGood]

Originally Posted by MrL_JaKiri

Just straight replacement, not multiplication

S'up with B, and F not being equal to zero then? And E for that matter as 07 is pretty pointless but could still be valid?

[Nodrog]

Originally Posted by JonnyBGood

S'up with B, and F not being equal to zero then? And E for that matter

If B or F was zero then D would also be zero, and its given that every number represented by a single letter. If E was zero then G would be zero, because you cannot get a 5 digit number when multiplying a 3 digit number by one which is one digit.

[acropolis]

Originally Posted by JonnyBGood

S'up with B, and F not being equal to zero then? And E for that matter as 07 is pretty pointless but could still be valid?

if b or f is 0, then D is 0 too. contradiction.

if E is 0, then 7xx * 9 < 10000, and your first digit will be 0. contradiction.