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Unread 11 Jan 2004, 21:51   #1
Tobe
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maths?
intergral cot^4 x between pi/6 and 0 with explanation would be handy as i m doing p4 tomorrow and this came up in book and didnt know what the hell to do does cot^2 have a relationship with something
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Unread 11 Jan 2004, 21:53   #2
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Re: maths?
get a TI83 silver edition, plug in cotangent^4 x between pi/6 (radians i take it) and 0.

not sure about the explenation, not doing p4 till summer i dont think.
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Unread 11 Jan 2004, 21:55   #3
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Re: maths?
i ve got a casio 7850 or something like that it wont let me plug in stuff like sin^2 but i m hoping sinsinx=sin^2 x
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Unread 11 Jan 2004, 21:57   #4
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Re: maths?
Quote:
Originally Posted by Tobe
i ve got a casio 7850 or something like that it wont let me plug in stuff like sin^2 but i m hoping sinsinx=sin^2 x
How the hell can you be doing P4 and not understand trigonometric operations?

And even if you did just plug it in, you'd only get 1 mark from a probable 4 (or even 6)
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Unread 11 Jan 2004, 21:59   #5
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Re: maths?
i take it you know what cotangent is....
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Unread 11 Jan 2004, 22:00   #6
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Re: maths?
is your casio a graphical calc? if not, buy the ti83 silver (in fact, buy it anyway, you can put doom 1 on it!!!!)
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Unread 11 Jan 2004, 22:03   #7
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Re: maths?
yes it is a graphics calculator, **** you jakiri do it and stop wasting my time
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Unread 11 Jan 2004, 22:06   #8
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Re: maths?
Hes trying to help but subtly hinting "learn basic maths".
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Unread 11 Jan 2004, 22:06   #9
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Re: maths?
read a book, it should say (MEI ones are good, if yer collage doesn't provide them, buy a P4 book).
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Unread 11 Jan 2004, 22:07   #10
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Re: maths?
don't let him cow you. ^^
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Unread 11 Jan 2004, 22:09   #11
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Re: maths?
its not basic maths **** off you gay
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Unread 11 Jan 2004, 22:09   #12
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Re: maths?
i dont have a fecking clue about this, i'm only half way through P2.
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Unread 11 Jan 2004, 22:12   #13
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Re: maths?
(cot x)4 = (1-(sin x)2)2/(sin x)4
= (cosec x)4 - 2×(cosec x)2 + 1 (expanding)


Now, (cosec x)4 = (1 + (cot x)2)×(cosec x)2
= (cosec x)2 + (cosec x)2 × (cot x)2

So,
(cot x)4= (cosec x)2*cot x)2 - (cosec x)2 + 1
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Unread 11 Jan 2004, 22:19   #14
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Re: maths?
Quote:
Originally Posted by Tobe
i ve got a casio 7850 or something like that it wont let me plug in stuff like sin^2 but i m hoping sinsinx=sin^2 x
I don't know about your calculator but that would be wrong on mine (and most i assume)

sinsinx implies sin(sinx) to me, not sin²x which you want

just put in numbers to see what your calculator does
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Unread 11 Jan 2004, 22:19   #15
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Re: maths?
Quote:
Originally Posted by Tobe
(cot x)4 = (1-(sin x)2)2/(sin x)4
= (cosec x)4 - 2×(cosec x)2 + 1 (expanding)


Now, (cosec x)4 = (1 + (cot x)2)×(cosec x)2
= (cosec x)2 + (cosec x)2 × (cot x)2

So,
(cot x)4= (cosec x)2*cot x)2 - (cosec x)2 + 1

http://www.nrich.maths.org.uk/mathsf...aams/q102.html

the paste doesnt show the superscripts of the pwoers

and youve missed out the last part

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Unread 11 Jan 2004, 22:23   #16
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Re: maths?
yeah i missed out the intergral was looking for an explanation of why sec^4 x = ..1-...
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